Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The sides of triangle are in the ratio 1: √3: 2, then the angles of the triangle are in ratio
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. The sides of triangle are in the ratio $1 : \sqrt{3} : 2$, then the angles of the triangle are in ratio
WBJEE
WBJEE 2007
A
$1 : 3 : 5$
B
$2 : 3 :1$
C
$3 : 2 :1$
D
$1 : 2 : 3$
Solution:
Given, $a : b : c=1 : \sqrt{3} : 2$
Here, $c^{2}=a^{2}+b^{2}$
$\therefore \Delta$ is right angled at $C$.
$\therefore \angle C=90^{\circ}$ and $\frac{a}{b}=\frac{1}{\sqrt{3}}$
$\Rightarrow \tan A=\frac{1}{\sqrt{3}}$
$\Rightarrow A=30^{\circ}$ and $B=60^{\circ} \,\,\,[$ as $A+B=90^{\circ}]$
$\therefore $ Ratio of angles $=A: B: C$
$=30^{\circ}: 60^{\circ}: 90^{\circ}=1: 2: 3$