The equation of sphere is $ {{x}^{2}}+{{y}^{2}}+{{z}^{2}}=54 $ The centre and radius of this sphere are (0, 0, 0) and $ \sqrt{54}, $ ie, $ 3\sqrt{6} $ . Distance between (1, 2, -1) and (0, 0, 0) is $ \sqrt{6} $ .
$ \therefore $ Shortest distance between point $ (1,2,-1) $ and surface of the sphere
$=3\sqrt{6}-\sqrt{6} $
$=2\sqrt{6} $