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Q.
The shortest distance between line $y-x=1$ and curve $x=y^{2}$ is
AIEEEAIEEE 2011Conic Sections
Solution:
The equation of the tangent to $x=y^{2}$ having slope
1 is $y=x+\frac{1}{4}$
Hence shortest distance $=\left|\frac{1-\frac{1}{4}}{\sqrt{2}}\right|$
$=\frac{3}{4 \sqrt{2}}=\frac{3 \sqrt{2}}{8}$ units