Shape of $X e F _{5}^{-} \rightarrow$
The Xe show $s p^{3} d^{3}$-hybridisation in $XeF _{5}^{-}$,
Thus, its geometry is Pentagonal-bipyramidal.
But, number of electron pair $=\frac{8+5+1}{2}=7$
Number of bond pair $=5^{2}$, number of lone pair $= 2$ .
A lot of electrons are present at axil position and all bonds are in same plane.
Hence, the shape is planar.