Question

The shape of $[PtCl_3(C_2H_4)]^-$ and the hybridisation of $Pt$ respectively are

• A. tetrahedral, $sp^3$
• B. trigonal pyramidal, $sp^3$
• C. square planar, $d\,sp^2$
• D. square planar, $d^2\,sp^3$

Answer 1

Answer: (C)

Zeise's salt : $\left[ K \left[ PtCl _{3}\left(\eta^{2}- C _{3} H _{4}\right)\right]\right.$ is a

$\pi$ -complex and square planar in structure with $d s p^{2}$ hybridisation.



Hybridisation in $\left[ Pt Cl _{3}\left(\eta^{2}- C _{2} H _{4}\right)\right]^{-}$

Pt atom : $4 d^{8} \,5 s^{2}$





As $Cl ^{-}$ ions and $C _{2} H _{4}$ approaches, the pairing of the unpaired electrons of $d$ orbitals takes place.

$\therefore \left[ Pt Cl _{3}\left( C _{2} H _{4}\right)\right]$