Thank you for reporting, we will resolve it shortly
Q.
The shape of $ IF_7$ molecule is
AFMCAFMC 2010The p-Block Elements - Part2
Solution:
Number of hybrid orbitals,
$H=\frac{1}{2}[V+M+A-C]$
(where, $V=$ number of valence electrons of central atom)
$M=$ number of monovalent atoms
$A=$ negative charge
$C=$ positive charge]
$\therefore H=\frac{1}{2}[7+7+0-0]=7$
Thus, the hybridisation of $IF_{7}$ is $s p^{3} d^{3}$ and its geometry is pentagonal bipyramidal.