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Q.
The set $\left\{x: x^4=1\right.$ and $\left.x \in R\right\}$ is ...X... set. Here, $X$ refers to
Sets
Solution:
Given equation is $x^4=1$
$\Rightarrow x^4-1 =0 $
$ \Rightarrow \left(x^2-1\right)\left(x^2+1\right) =0 $
$ \Rightarrow (x-1)(x+1) =0 $$ \left( \because x^2 \neq-1, x \in R\right)$
$ \Rightarrow x =-1,1 $
Hence, the given set is $\{-1,1\}$.