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Q. The set of value(s) for $K$ for which the equation $\left|x^2-5\right| x|+6|=2 K$ has eight real and distinct solution is

Complex Numbers and Quadratic Equations

Solution:

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$\left| x ^2-5\right| x |+6|=2 K$ has eight real and distinct solutions, then
$0<2 K <\frac{1}{4} $
$0< K <\frac{1}{8} $