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  4. The set A = x: x ∈ R, x2 = 16 and 2x = 6 equals

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Q. The set $A = \{ x : x \in R, x^2 = 16$ and $2x = 6\}$ equals

BITSATBITSAT 2011

Solution:

Since, $x^{2}=16 $
$\Rightarrow x=\pm 4$
and $2 x=6$
$ \Rightarrow x=3$
Hence, no value of $x$ is satisfied.
$\therefore A =\phi$