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  4. The set A = x: x ∈ R, x2 = 16 and 2x = 6 equals

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Q. The set A = {x : x $\in$ R, $x^2$ = 16 and 2x = 6} equals

Sets

Solution:

We have $x^2 = 16 \, \Rightarrow \, x = \pm 4$
Also, 2x = 6 $\Rightarrow $ x = 3
There is no value of x which satisfies both the above equations. Thus the set A contains no elements.
$\therefore \, A = \phi$