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Q. The set (A / B) $\cup$ (B / A) is equal to

Sets

Solution:

Given set can be written as
$(A - B) \cup (B - A) = (A \cup B) - (A \cap B)$
(By definition of symmetric difference)
Hence, (A \ B)$ \cup $(B \ A)$ = (A \cup B) $\ $(A \cap B)$