1. Tardigrade
  2. Question
  3. Mathematics
  4. The series of positive multiples of 3 is divided into sets: 3 6,9,12 15,18,21, 24,27 ldots Then the sum of the elements in the 11 text th set is equal to

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The series of positive multiples of $3$ is divided into sets : $\{3\},\{6,9,12\},\{15,18,21$, $24,27\}, \ldots$ Then the sum of the elements in the $11^{\text {th }}$ set is equal to_______

JEE MainJEE Main 2022Sequences and Series

Solution:

$ S _{11}=3[101+102+\ldots \ldots+121] $
$ =\frac{3}{2}(222) \times 21=6993$