Thank you for reporting, we will resolve it shortly
Q.
The sensitivity of a galvanometer is 60 divisions per ampere. When a shunt is used its sensitivity
becomes 10 divisions per ampere. If the galvanometer is of $20\,\Omega$ resistance, the value of the shunt
is :
Solution:
Let the number of divisions on the scale be $n$. Then $I_g = \frac{n}{60}$ and $I = \frac{n}{10}$ ,
Also $I_g \times 20 = ( I - I_g)S$
This gives $S$ = 4.