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Physics
The second overtone of an open organ pipe has the same frequency as the first overtone of a closed pipe L metre long. The length of the open pipe will be
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Q. The second overtone of an open organ pipe has the same frequency as the first overtone of a closed pipe $L$ metre long. The length of the open pipe will be
NEET
NEET 2016
Waves
A
$L$
7%
B
$2L$
62%
C
$\frac{L}{2}$
20%
D
$4L$
11%
Solution:
$\frac{3v}{2\ell_{0}} = \frac{3v}{4L}$
$ 2\ell_{0} = 4L $
$ \ell_{0} = 2L $