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Q. The rusting of iron takes place as follows $ RCOCl+{{H}_{2}}\xrightarrow{Pd/BaS{{O}_{4}}}RCHO+HCl $ $ BaS{{O}_{4}} $ Calculate $ HCl $ for the net process.

BVP MedicalBVP Medical 2014

Solution:

Reactions, (i) $ C{{l}^{-}} $ and $ 825\times {{10}^{14}}M $ (ii) $ 1.65\times {{10}^{13}}M $ and $ 2.87\times {{10}^{6}}M $ Net reaction $ 6.72\times {{10}^{6}}M $ $ {{K}_{f}} $ $ -{{0.360}^{o}}C $ $ =-0.88-2.46 $ $ =-3.34F=-3.34\times 96500J $ $ =-322.31kJ=-322kJ $