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Q. The root mean square velocity of hydrogen molecules of an ideal hydrogen gas kept in a gas chamber at $0^{\circ} C$ is $3180 \,m / s$. Calculate the pressure of hydrogen gas: (Density of hydrogen gas $=8.99 \times 10^{-2} \,kg / m ^{3}$, atmosphere $\left.=1.01 \times 10^{5}\, N / m ^{2}\right)$

JIPMERJIPMER 2003

Solution:

$ P =\frac{1}{3} \rho e^{2} $
$=\frac{1}{3} \times 8.99 \times 10^{-2} \times(3180)^{2} N / m ^{2} $
$=\frac{1}{3} \times \frac{8.99 \times 10^{-2} \times(3180)^{2}}{1.01 \times 10^{5}}$ atm
$=3 $ atm