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Q. The Rolle's theorem is applicable in the interval $ \alpha =\frac{\gamma }{3}=\frac{6\times {{10}^{-5}}}{3}=2\times {{10}^{-5}}{{/}^{o}}c $ for the function

JamiaJamia 2015

Solution:

Let $ f(x)={{x}^{2}} $ $ \therefore $ $ f(1)=f(-1)=1 $ Also, f(x) is continuous and differentiable in the given interval.