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  4. The reverse breakdown voltage of Zener diode is 5.6V in the given circuit. The current Iz through the Zener is:- <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/p-c7u17lsrjmbexuv2.jpg />

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Q. The reverse breakdown voltage of Zener diode is $5.6V$ in the given circuit. The current $I_{z}$ through the Zener is:-
Question

NTA AbhyasNTA Abhyas 2020

Solution:

Solution
In first loop
$9V=200I_{1}+5.6V$
$I_{1}=\frac{3 . 4}{200}=17mA$
In second loop
$I_{2}=\frac{5 . 6}{800}=7mA$
$I_{Z}=I_{1}-I_{2}$
$=\left(\right.17-7\left.\right)mA=10mA$