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Q. The resultant of two forces, one double the other in magnitude, is perpendicular to the smaller of the two forces. The angle between the two forces is

KCETKCET 2002Laws of Motion

Solution:

$\operatorname{Cos} \theta=\frac{P}{2 P}$
$ \theta=60^{\circ} $
angle between force $P$ and $2 P$ is $120^{\circ}$