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Q. The resultant of two forces acting at an angle of $120^{\circ}$ is $10\, kg$ wt and is perpendicular to one of the forces . That force is .......

KCETKCET 2011Motion in a Plane

Solution:

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Here, $\tan 30^{\circ}=\frac{1}{\sqrt{3}}$
$\frac{1}{\sqrt{3}}=\frac{x}{10}$
$x=\frac{10}{\sqrt{3}}, kg - wt$