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Q.
The resultant capacity between the points P and Q of the given figure is
Electrostatic Potential and Capacitance
Solution:
As seen from the circuit, between $P$ and $Q$ there is a combination of three capacitors.
In this combination two $4 \,\mu F$ capacitors are connected in series and this series connection is connected in parallel to the $2\, \mu F$ capacitor.
So, effective capacitance of the series combination:
$\frac{1}{ C _{\text {eff }}}=\frac{1}{ C _{1}}+\frac{1}{ C _{2}}$
or, $\frac{1}{ C _{\text {eff }}}=\frac{1}{4}+\frac{1}{4}$
or, $C _{\text {eff }}=2 \,\mu F$
Now, this $2 \,\mu F$ capacitance comes in parallel with the $2 \,\mu F$ capacitance.
So, effective capacitance of this parallel combination:
$C _{\text {eff }}'= C _{1}+ C _{2}$
or, $C _{\text {eff }}'=2 \,\mu F +2 \,\mu F$
or, $C _{\text {eff }}'=4 \,\mu F$
