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Q.
The resistor $R_1 = 3 \Omega$ and $R_2 = 1 \Omega$ are connected in parallel to a 20 V battery. Find the heat developed in the resistor $R_{1}$ in one minute
A circuit with two resistances $3 \Omega$ and $1 \Omega$ are connected with $20 V$ battery is as shown in figure below
Since resistors are connected in parallel, so each branch of the circuit has potential drop of $20\,V$.
$\therefore $ Current in $R_{1}$ resistor, $I=\frac{V}{R_{1}}=\frac{20}{3} A$
$\therefore $ Heat developed in $R_{1}$ is given by $H=I^{2} R_{1} t$
where, $t=1 \min =60\,s$
$\Rightarrow H=\frac{20}{3} \times \frac{20}{3} \times 3 \times 60=8000\,J$
