Question

The resistance of the cell containing $KCl$ solution at $23^{\circ} C$ was found to be $55\, \Omega$. Its cell constant is $0.616\, cm ^{-1}$. The conductivity of $KCl$ solution $\left(\Omega^{-1} cm ^{-1}\right)$ is

• A. $1.21 \times 10^{-3}$
• B. $1.12 \times 10^{-2}$
• C. $1.12 \times 10^{-3}$
• D. $1.21 \times 10^{-2}$

Answer 1

Answer: (B)

Conductivity, $\kappa=\frac{\text { Cell constant }}{\text { Resistance }}=\frac{0.616}{55}$
$=1.12 \times 10^{-2} \Omega^{-1} cm ^{-1}$