Question

The resistance of N/10 solution is found to be $ 2.5\times {{10}^{3}} $ ohm. The equivalent conductance of the solution is (cell constant = 1.25 $ c{{m}^{-1}} $ )

• A. $ 2.5\,\,oh{{m}^{-1}}c{{m}^{2}}equi{{v}^{-1}} $
• B. $ 5.0\,\,oh{{m}^{-1}}c{{m}^{2}}equi{{v}^{-1}} $
• C. $ 2.5\,\,oh{{m}^{-1}}c{{m}^{2}}equi{{v}^{-1}} $
• D. $ 5.0\,\,oh{{m}^{-1}}c{{m}^{2}}equi{{v}^{-1}} $

Answer 1

Answer: (B)

Resistance of N/10 solution $ =2.5\times {{10}^{3}}\Omega $ $ \kappa =\frac{1}{\text{resistance}}\times \text{cell}\,\text{constant} $ $ =\frac{1}{2.5\times {{10}^{3}}}\times 1.25 $ $ =\frac{1.25\times {{10}^{-3}}}{2.5}=5\times {{10}^{-4}}\text{oh}{{\text{m}}^{-1}}\text{c}{{\text{m}}^{-1}} $ Equivalent conductance $ =\frac{\kappa \times 1000}{M} $ $ =\frac{5\times {{10}^{-4}}\times 1000}{1/10} $ $ =5\,\text{oh}{{\text{m}}^{-1}}\,\text{c}{{\text{m}}^{2}}\,\text{equ}{{\text{i}}^{-1}} $