Question

The resistance of conductivity cell containing $0.001MKCl$ solution at $298K$ is $1500 \, \Omega$ . What is the cell constant if conductivity of $0.001MKCl$ solution at $298 \, K$ is $0.146\times 10^{- 3} \, Scm^{- 1}.$

• A. $0.200 \, cm^{- 1}$
• B. $0.219 \, cm^{- 1}$
• C. $0.195 \, cm^{- 1}$
• D. $0.190 \, cm^{- 1}$

Answer 1

Answer: (B)

Cell constant $=\frac{c o n d u c t i v i t y}{c o n d u c tan c e}$
$=$ Conductivity $\times $ Resistance
$=0.146\times 10^{- 3} \, Scm^{- 1}\times 1500 \, \Omega$
$=0.219 \, cm^{- 1}$