Question

The resistance of $0.01\, N$ solution of an electrolyte was found to be $220 \,ohm$ at $298\, K$ using a conductivity cell with a cell constant of $0.88 \,cm ^{-1}$. The value of equivalent conductance of solution is -

• A. $400\, mho \,cm ^{2}\, g \,eq ^{-1}$
• B. $295\, mho \,cm ^{2}\, g\, eq ^{-1}$
• C. $419 \,mho\, cm ^{2}\, g \,eq ^{-1}$
• D. $425\,mho\, cm ^{2} \,g\, eq ^{-1}$

Answer 1

Answer: (A)

$\Lambda_{ eq }=\kappa \times \frac{1000}{N}=\frac{1}{R} \times \frac{l}{a} \times \frac{1000}{N}$
$=\frac{1}{R} \times $ cell constant $ \times \frac{1000}{N}=\frac{1}{220} \times 0.88 \times \frac{1000}{0.01} $
$=400\, mho \,cm ^{2}\, g \,eq ^{-1}$