Question

The resistance of $0.01 \,N \,NaCl$ solution at $25^{\circ} C$ is $200 \,\Omega$. Cell constant of conductivity cell is $1\, cm ^{-1}$. The equivalent conductance is :

• A. $5 \times 10^{2} \Omega^{-1} cm ^{2} eq ^{-1}$
• B. $6 \times 10^{3} \Omega^{-1} cm ^{2} eq ^{-1}$
• C. $7 \times 10^{4} \Omega^{-1} cm ^{2} eq ^{-1}$
• D. $8 \times 10^{5} \Omega^{-1} cm ^{2} eq ^{-1}$

Answer 1

Answer: (A)

$\lambda=k \times V=\frac{1}{R} \times \frac{l}{a} \times V$
$=\frac{1}{200} \times 1 \times 10,000$
$=5 \times 10^{2} \Omega^{-1} cm ^{2} eq ^{-1}$