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  4. The remainder when 798 is divided by 5 is

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Q. The remainder when $7^{98}$ is divided by 5 is

Binomial Theorem

Solution:

$7^{98}=(50-1)^{49}={ }^{49} C _0(50)^{49}-{ }^{49} C _1(50)^{48}+\ldots . .+{ }^{49} C _{48} \times 50-{ }^{49} C _{49}$
Remainder $=5-1=4$