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Q. The remainder when $10^{10} \cdot (10^{10} + 1) (10^{10} + 2)$ is divided by $6 $ is

KCETKCET 2013Binomial Theorem

Solution:

Here, $10^{10} \cdot\left(10^{10}+1\right) \cdot\left(10^{10}+2\right)$ is a product of $3$ consecutive integers.
Therefore, it is divisible by $3 !$ i.e.,$ 6$ .
So, required remainder is $0$