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Q. The relationship between the force $F$ and position $x$ of a body is as shown in figure. The work done in displacing the body from $x = 1\, m$ to $x = 5\, m$ will be
image

Work, Energy and Power

Solution:

Work done = area under $F-x$ graph
= area of rectangle $ABCD +$ area of rectangle $LCEF$
+ area of rectangle $GFIH +$ area of triangle $IJK$
image
$=\left(2-1\right)\times\left(10-0\right)+\left(3-2\right)\left(5-0\right)+\left(4-2\right)\left(-5-0\right)$
$+\frac{1}{2}\left(5-4\right)\left(10-0\right)=15\, J$