Question

The relationship between the energy $ {{E}_{1}} $ of the radiation with a wavelength $ 8000\overset{\text{o}}{\mathop{\text{A}}}\, $ and the energy $ {{E}_{2}} $ of the radiation with a wavelength $ 16000\overset{\text{o}}{\mathop{\text{A}}}\, $ is:

• A. $ {{E}_{1}}=6{{E}_{2}} $
• B. $ {{E}_{1}}=2{{E}_{2}} $
• C. $ {{E}_{1}}=4{{E}_{2}} $
• D. $ {{E}_{1}}=1/2{{E}_{2}} $
• E. $ {{E}_{1}}={{E}_{2}} $

Answer 1

Answer: (B)

$ E=\frac{hc}{\lambda }, $ h and c for both cases are same so, $ \frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}=\frac{16000}{8000} $ $ {{E}_{1}}=2{{E}_{2}} $