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Q.
The relation between a, b, a' and b' such that the two lines ax + by = c and a'x + b'y = c' are perpendicular is
Straight Lines
Solution:
Slope of the line $ax + by = c$ is $\frac{-a}{b}$, and the slope of the line $a'x + b'y = c' $ is $\frac{-a'}{b'}$
The lines are perpendicular if $\left(\frac{-a}{b}\right)\left(\frac{-a'}{b'}\right) = - 1$ or $aa' + bb' = 0 $