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Q. The reduction potential of hydrogen half-cell will be negative if :

AIEEEAIEEE 2011

Solution:

$H ^{+}+ e ^{-} \longrightarrow \frac{1}{2} H _{2}$

Apply Nernst equation

$E =0 -\frac{0.059}{1} \log \frac{ P _{ H _{2}}^{\frac{1}{2}}}{\left[ H ^{+}\right]}$

$E =-\frac{0.059}{1} \log \frac{2^{1 / 2}}{1}$

Therefore $E$ is negative.