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Q. The reduction potential of hydrogen half-cell will be negative if

WBJEEWBJEE 2021

Solution:

Reaction $2 H ^{+}+2 e \rightarrow H _{2}$
$\therefore n=2, \,\, Q =\frac{P_{H_{2}}}{\left[H^{+}\right]^{2}} $
As $E_{H^{-} / H_{2}} =E_{H^{-} / H_{2}}^{\circ} \frac{-0.059}{n} \log Q$
$=-\frac{0.059}{2} \log Q $
$\therefore $ if $Q > 1 E_{H^{-} / H_{2}} < 0$
A $Q = \frac{1}{1} = 1$ X
B $Q = \frac{1}{2^2} < 1$ X
C $Q = \frac{2}{12} > 1$ $\checkmark$
D $Q = \frac{2}{2^2} < 1$ X