Q. The reduction potential of hydrogen half-cell will be negative if
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Solution:
Reaction $2 H ^{+}+2 e \rightarrow H _{2}$
$\therefore n=2, \,\, Q =\frac{P_{H_{2}}}{\left[H^{+}\right]^{2}} $
As $E_{H^{-} / H_{2}} =E_{H^{-} / H_{2}}^{\circ} \frac{-0.059}{n} \log Q$
$=-\frac{0.059}{2} \log Q $
$\therefore $ if $Q > 1 E_{H^{-} / H_{2}} < 0$
A
$Q = \frac{1}{1} = 1$
X
B
$Q = \frac{1}{2^2} < 1$
X
C
$Q = \frac{2}{12} > 1$
$\checkmark$
D
$Q = \frac{2}{2^2} < 1$
X
A | $Q = \frac{1}{1} = 1$ | X |
B | $Q = \frac{1}{2^2} < 1$ | X |
C | $Q = \frac{2}{12} > 1$ | $\checkmark$ |
D | $Q = \frac{2}{2^2} < 1$ | X |