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  4. The reduction potential of hydrogen electrode is 118 mV. The concentration of H+ in the solution is

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Q. The reduction potential of hydrogen electrode is $118\, mV$. The concentration of $H^{+}$ in the solution is

Electrochemistry

Solution:

$E_{cell}=\frac{0.0591}{n}log \left[H^{+}\right] $
$ -0.118=\frac{0.0591}{2} log \left[H^{+}\right]$
$\frac{0.118}{\frac{0.0591}{2}}=-log \left[H^{+}\right]$
$\Rightarrow pH=0.01M$