Question

The reducing agent in the reaction, $C_{2}O_{4}^{2 -}+MnO_{4}^{-}+H^{+}\overset{ \, }{ \rightarrow }Mn^{2 +}+CO_{2}+H_{2}O$ is:

• A. $C_{2}O_{4}^{2 -}$
• B. $MnO_{4}^{-}$
• C. $Mn^{2 +}$
• D. $H^{+}$

Answer 1

Answer: (A)

$\left[C_{2}^{+ 3} O_{4}\right]^{2 -}+\left[M_{n}^{+ 7} O_{4}\right]^{- 1}$
$M_{n}^{+ 2}+C O_{2}^{+ 4}+H_{2}O$
Reducing agent is that whose oxidation number increases.