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Physics
The recoil velocity of a 4.0 kg rifle that shoots a 0.050 kg bullet at a speed of 280 text ms-1 is:
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Q. The recoil velocity of a $ 4.0\, kg $ rifle that shoots a $ 0.050\, kg $ bullet at a speed of $ 280\text{ }m{{s}^{-1}} $ is:
KEAM
KEAM 2004
Laws of Motion
A
$ +3.5\text{ }m{{s}^{-1}} $
31%
B
$ -3.5\text{ }m{{s}^{-1}} $
42%
C
$ -\sqrt{(3.5)}\text{ }m{{s}^{-1}} $
11%
D
$ +\sqrt{(3.5)}\text{ }m{{s}^{-1}} $
7%
E
$ \text{+7 }m{{s}^{-1}} $
7%
Solution:
$ {{m}_{1}}{{u}_{1}}+{{m}_{2}}{{u}_{2}}=0 $
$ \Rightarrow $ $ {{u}_{1}}=-\frac{{{m}_{2}}{{u}_{2}}}{{{m}_{1}}} $
$ =\frac{0.050\times 280}{4}=-3.5\,m{{s}^{-1}} $