Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The recoil velocity of a $ 4.0\, kg $ rifle that shoots a $ 0.050\, kg $ bullet at a speed of $ 280\text{ }m{{s}^{-1}} $ is:

KEAMKEAM 2004Laws of Motion

Solution:

$ {{m}_{1}}{{u}_{1}}+{{m}_{2}}{{u}_{2}}=0 $
$ \Rightarrow $ $ {{u}_{1}}=-\frac{{{m}_{2}}{{u}_{2}}}{{{m}_{1}}} $
$ =\frac{0.050\times 280}{4}=-3.5\,m{{s}^{-1}} $