Question

The reagent required to convert propene to 1 -propanol is

• A. $B _{2} H _{6}$ followed by $H _{2} O _{2} / NaOH$
• B. conc. $H _{2} SO _{4}$ followed by hydrolysis with boiling water
• C. HBr followed by hydrolysis with aqueous $KOH$
• D. $Hg \left( OCOCH _{3}\right)_{2}$ followed by reduction with $NaBH _{4}$.

Answer 1

Answer: (A)

Anti-Markownikoff's hydration occurs by hydroboration-oxidation of alkenes.

$CH _{3} CH = CH _{2} \xrightarrow[{(ii)H_2O_2/OH^-}]{{(i)B_2H_6}} \underset{\text{Anti-Markownikoff's product}}{CH _{3} CH _{2} CH _{2} OH}$

Other three options will lead to Markownikov's hydration, i.e.,

$CH _{3} CH = CH _{2} \longrightarrow CH _{3} CHOHCH _{3}$