Since, the voltage across inductor and capacitor is same, so they are in resonance i.e.,$X_L=X_C$
The impedance of circuit,
$Z=\sqrt{R^2+\left(X_L-X_C\right)^2}=R$
$\therefore$ Voltage across, $R=220 V$
By Ohm's law, $V=I R$
$\Rightarrow I=\frac{V}{R}=\frac{220}{100}=2.2\, A$
Hence, ammeter reading is $2.2 \,A$ and voltmeter reading is $220 \,V$.
