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Q. The reading of the ideal ammeter will be (Resistance of ideal ammeters is zero)



Question

NTA AbhyasNTA Abhyas 2020Current Electricity

Solution:

$R_{e q}=3 ||6 + 2 = 2 + 2 = 4 \Omega $
Current from Battery, $I=\frac{V}{R_{e q}}=\frac{10}{4}=2.5A$
Solution
$I_{1}=2.5\times \frac{3}{3 + 6}=\frac{5}{6} \, A$