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Q.
The reading of the ammeter as per figure shown is
Current Electricity
Solution:
Resistance across $X Y=\frac{2}{3} \Omega$
Total resistance $=2+\frac{2}{3}=\frac{8}{3} \,\Omega$
Current through ammeter $=\frac{2}{8 / 3}=\frac{6}{8}=\frac{3}{4} A$