Tardigrade
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Chemistry
The reactivity of the compounds (i) MeBr (ii) PhCH 2 Br (iii) MeCl (iv) p -MeOC 6 H 4 Br decreases as
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Q. The reactivity of the compounds (i) $MeBr$ (ii) $PhCH _{2} Br$ (iii) $MeCl$ (iv) $p -MeOC _{6} H _{4} Br$ decreases as
Haloalkanes and Haloarenes
A
$( i )>( ii )>( iii )>( iv )$
B
$(iv) >( ii )>( i )>( iii )$
C
$(iv) >( iii )>( i )>( ii )$
D
$( ii )>( i )>( iii )>( iv )$
Solution:
The order of reactivity follows the sequence :
benzyl halides $>$ alkyl halides $>$ aryl halides.
Out of chloride and bromides, bromides are more reactive. Therefore, the correct order of reactivity is
$PhCH _{2} Br ( ii )> MeBr ( i )> MeCl ( iii )>p- MeOC _{6} H _{4} Br ( iv )$