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Chemistry
The reaction of (S)-2-bromobutane with OH- to produce (R)-butan-2-ol will be
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Q. The reaction of (S)-2-bromobutane with $OH^{-}$ to produce (R)-butan-2-ol will be
NTA Abhyas
NTA Abhyas 2022
A
first order in 2-bromobutane only
B
first order in $OH^{-}$ only
C
first order in 2-bromobutane and first order in $OH^{-}$
D
second order in $OH^{-}$
Solution:
Configuration invert, means $\text{S}_{\text{N}} ^{2}$ reaction takes place
Rate $=$ K[Substrate] $\left[\right.OH^{-}\left]\right.$