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Chemistry
The reaction of P4 with X leads selectively to P4O6. The X is
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Q. The reaction of $P_4$ with X leads selectively to $P_4O_6$. The X is
UPSEE
UPSEE 2019
A
dry $O_2$
0%
B
a mixture $O_2$ and $N_2$
0%
C
moist $O_2$
100%
D
$O_2$ in the presence of aqueous NaOH
0%
Solution:
When phosphorous is burnt in limited supply of air, formation of $P_4O_6$ occur.
$\because \ce{P4 +air -> P4O6}$
$\therefore \ce{P4 +3O2 + N2 -> P4O6 +N2}$
Nitrogen is used here to retard the further oxidation.