1. Tardigrade
  2. Question
  3. Chemistry
  4. The reaction of ozone with oxygen atoms in the presence of chlorine atoms can occur by a two step process shown below: O3 (g) + Cl* (g) → O2 (g) + ClO* (g) dots (i) [ki = 5.2 × 109 L mol-1 s-1] ClO* (g) + O* (g) → + Cl* (g) dots (ii) [kii = 2.6 × 1010 L mol-1 s-1] The closest rate constant for the overall reaction O3(g)+O*(g) → 2O2(g) is :

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Q. The reaction of ozone with oxygen atoms in the presence of chlorine atoms can occur by a two step process shown below :
${O_3 (g) + Cl^{*} (g) \to O_2 (g) + ClO^{*} (g)}\, \dots (i) $
$[k_{i} = 5.2 \times 10^{9} \, L \, mol^{-1} \, s^{-1}]$
${ClO^{*} (g) + O^{*} (g) \to + Cl^{*} (g) }\,\dots (ii)$
$[{k_{ii} = 2.6 \times 10^{10} \, L \, mol^{-1} s^{-1}}]$
The closest rate constant for the overall reaction
$O_{3}(g)+O^{*}(g) \to 2O_{2}(g)$ is :

JEE MainJEE Main 2016Chemical Kinetics

Solution:

$O _{3}( g )+ Cl ^{\prime}( g ) \rightarrow O _{2}( g )+ ClO ( g ) \ldots .$ (i) $k _{ i }=5.2 \times 10^{9} L mol ^{-1} s ^{-1}$
$ClO ^{\prime}( g )+ O ^{\prime}( g ) \rightarrow O _{2}( g )+ Cl ^{\prime}( g ) \ldots$ (ii) $k _{ ii }=2.6 \times 10^{10} L mol ^{-1} s ^{-1}$
For overall reaction, equation (i)+(ii)
$ O _{3}( g )+ O ( g ) \rightarrow 2 O _{2}( g )
Then overall reaction constant will be $k _{ i } \times k _{ ii }$.
So, overall reaction constant is $1.4 \times 10^{20} Lmol ^{-1} s ^{-1}$.