Q.
The reaction of $K _{3}\left[ Fe ( CN )_{6}\right]$ with freshly prepared $FeSO _{4}$ solution produces a dark blue precipitate called Turnbull's blue. Reaction of $K _{4}\left[ Fe ( CN )_{6}\right]$ with the $FeSO _{4}$ solution in complete absence of air produces a white precipitate $X$, which turns blue in air. Mixing the $FeSO _{4}$ solution with $NaNO _{3}$, followed by a slow addition of concentrated $H _{2} SO _{4}$ through the side of the test tube produces a brown ring.
Among the following, the brown ring is due to the formation of
JEE AdvancedJEE Advanced 2021
Solution: