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Q. The reaction of $K _{3}\left[ Fe ( CN )_{6}\right]$ with freshly prepared $FeSO _{4}$ solution produces a dark blue precipitate called Turnbull's blue. Reaction of $K _{4}\left[ Fe ( CN )_{6}\right]$ with the $FeSO _{4}$ solution in complete absence of air produces a white precipitate $X$, which turns blue in air. Mixing the $FeSO _{4}$ solution with $NaNO _{3}$, followed by a slow addition of concentrated $H _{2} SO _{4}$ through the side of the test tube produces a brown ring.
Among the following, the brown ring is due to the formation of

JEE AdvancedJEE Advanced 2021

Solution:

$FeSO _{4}+ NaNO _{3}+ H _{2} SO _{4} \longrightarrow \left[ Fe \left( H _{2} O \right)_{5} NO \right]^{+2}+ SO _{4}^{-2}$