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  4. The reaction of butanal with n-propylmagnesium bromide gives a

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Q. The reaction of butanal with $n$-propylmagnesium bromide gives a

KVPYKVPY 2009

Solution:

The reaction of butanal with $n$-propyl magnesium bromide (Grignard reagent) gives heptan$-4-ol$, which is a secondary alcohol as the $2$ functional groups $(— CH_2CH_2CH_3)$ are same, so the formed alcohol is a chiral.
$CH_3CH_2CH_2CHO+ CH_3 CH_2CH_2MgBr$
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