Question

The reaction conditions leading to the best yield of $C_{2}H_{5}Cl$ are:

• A. $C_{2}H_{6}(excess)+Cl_{2} \xrightarrow{uv\,light}$
• B. $C_{2}H_{6}+Cl_{2} \xrightarrow[\text{room temperature}] { \text{dark}}$
• C. $C_{2}H_{6} + Cl_{2} $ (excess) $\xrightarrow{UV \text{light}}$
• D. $C_{2}H_{6} + Cl_{2}\xrightarrow{UV \text{light}}$

Answer 1

Answer: (A)

Chlorination beyond monochlorination during the preparation of alkyl halides in presence of UV light can be suppressed by taking alkane in excess. In (b) free radical substitution can’t take place in dark.