Thank you for reporting, we will resolve it shortly
Q.
The ratios of the distance traversed in successive intervals of time by a body, falling from rest, are
Motion in a Straight Line
Solution:
Initially u = 0
Distance travelled in the nth second is given by
$h_n=u+\frac{g}{2}(2n-1)$
Distance travelled in the 1st second is
$h_1=0+\frac{g}{h}(2 \times 1-1)=\frac{g}{2}$
Distance travelled in the 2nd second is
$h_2=0+\frac{g}{h}(2 \times 2-1)=\frac{3g}{2}$
Distance travelled in 3rd second
$h_3=0+\frac{g}{2}(2 \times 3-1)=\frac{5g}{2}$
The ratio of distances
$h_1:h_2:h_3:h_4:h_5:......=1:3:5:7:....$