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  3. Chemistry
  4. The ratio t7 / 8: t1 / 2 for the first order reaction is

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Q. The ratio $t_{7 / 8}: t_{1 / 2}$ for the first order reaction is

Chemical Kinetics

Solution:

$t _{7 / 8}=\frac{2.303}{ K } \log \frac{ a }{ a -\frac{7}{8} a }=\frac{2.08}{ K }$

$t _{1 / 2}=\frac{2.303}{ K } \log \frac{ a }{\left( a -\frac{ a }{2}\right)}=\frac{0.693}{ K }$

$\therefore \,\,\,\, \frac{ t _{7 / 8}}{ t _{1 / 2}}=3$